Medvedev won his first year-end win 2-0! Sent the Australian star out of the game, and knocked the world No. 1 Sinner in the final round

In the second round of the ATP year-end finals in the second round of the Stasse group, which ended on the evening of November 12, Beijing time, Russian star Medvedev swept the Australian good player De Minaur in straight sets with a score of 6-2 and 6-4, and retained the hope of promotion after winning the first victory at the end of the year, while De Minaur, who lost twice in a row, was out of the group early.

In the first round, Medvedev, as the No. 4 seed, was swept 0-2 by Fritz, and he was also booed by the crowd for his actions such as smashing rackets and negative matches. In this round, he will face the world No. 7 De Minaur. The two sides have played each other 9 times before, and Medvedev has the upper hand with 6 wins and 3 losses.

In the first set, Medvedev took the lead in the third set and won five games in a row to establish a 5-1 advantage after 0-1. In the end, Medvedev won the first set 6-2. In the second set, the two sides played very fiercely. The first 8 games were held separately. In the crucial ninth game, Medvedev broke first. In the 10th game, Medvedev won the service game smoothly and won the second set 6-4, thus defeating De Minaur 2-0 on aggregate and giving the Australian star two consecutive defeats.

The victorious Medvedev has a 1-1 record and retains his hopes of advancing to the semifinals. De Minaur, on the other hand, is at the bottom of the tournament with 2 consecutive defeats and is out early. In the last game, Medvedev will face Sinner, and it will be important to qualify and win this game.